The equation for line G is given by 5y=-2x-205y=−2x−20. Suppose line G is parallel to line R, and line E is perpendicular to line G. Point (-10, 8) lies on both line R and line E. Choose the correct equation for R and E from the choices below. Line E: y=\frac{5}x+33y= x 5 +33 Line R: y=-\frac{2}{5}x+4y=− 5 2 x+4 Line E: y=\frac{5}{2}x+33y= 2 5 x+33 Line R: y=-\frac{2}x+4y=− x 2 +4 Line R: y=-\frac{5}{2}x+8y=− 2 5 x+8

The answer is 270 cars.you can do this by making a proportional relationship. for instance, 200 is the whole we are using, so on a “number line” 200 would be over 100%. now, since he sells 35% more, add 35% to 100% to get 135% on the other side of the “number line” on the bottom half, leaving the top half empty.cross multiply 200 by 135 then divide by 100 to get your answer. i hope this , if it did, , if you don’t mind, giving me brainiest! 200/100% } 200 • 135 /100 ? /135%