The sum of three consecutive multiples of 4 is 444. Find the multiples.
PLEASE ANS FAST PLS

144,148,152

Step-by-step explanation:

Here we will have, 4x + 4(x+1) + 4(x+2) = 444

=> x + (x+1) + (x+2) = 111 (dividing both sides by 4)

=>x + x+1 + x+2 =111

=> 3x + 3 = 111

=> 3x = 108

=> x = 36.

So, the three desired numbers 4x, 4(x+1) and 4(x+2) are,

4*36, 4*(36+1) and 4*(36+2)

That means the numbers are, 144, 148 and 152.

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

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step-by-step explanation: