A tourist in France wants to visit 10 different cities. If the route is randomly selected, what is the probability that she will visit the cities in alphabetical order?

1/3628800

Step-by-step explanation:

This question requires that we calculate

1/number of permutations of 10 cities

= P(n,k) = n!/(n-k)!

We have

n = 10

k = 10

= 10!/(10-10)!

= 10!

number of permutations of 10 cities 10! This Is equal to 3,628,800

From this answer we the probability of doing a random tour of these 10 different cities in alphabetical order.

And this is

= 1/3,628,800

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step-by-step explanation:

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d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it