A rectangle has an area of 120 square cm. Its length and width are whole numbers. List the possible dimensions of the rectangle. Which possibility gives the smallest perimeter?

kindly check explanation

Step-by-step explanation:

Given that:

Area of rectangle = 120 cm²

Assume ; Length and width are whole numbers

Possible dimension of the rectangle will be :

Area of a rectangle = Length × width

Area = 120cm²

Possible dimensions :

80cm by 1 cm

40cm by 2cm

20cm by 4cm

10cm by 8cm

5cm by 16cm

Possibility which gives the smallest perimeter :

Dimension = 10cm by 8cm

Perimeter of Rectangle = 2(length + width)

Perimeter of Rectangle :

= 2(10 + 8)cm

= 2(18)cm

= 36cm

hi, i am not sure about this one but i think its d,

hope this !

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12