3 Consider the set X = { 1 , 2 , 3 , 4 , 5 } and suppose you have two holes. Also suppose that you have 10 pigeons: the 2 -element subsets of X . Can you put these 10 pigeons into the two holes in a way that there is no 3 -element subset S = { a , b , c } ⊂ X for which all pigeons from S go in the same hole? Then answer the same question if X = { 1 , 2 , 3 , 4 , 5 , 6 } with 15 = C ( 6 , 2 ) pigeons.

dalila is incorrect. the whisker on the left is very long, going all the way out to 5. the whisker goes from 5 to 30, so it has a spread of 25. the rest of the box plot values are closer together, so 5 is an outlier

60: 45 =12: 9 =4: 3 so the answer is 4: 3

answer: sorry i dont really know but can we talk all my friends r gone and im bored

step-by-step explanation:

good luck on ur quiz test or homework. have a good day : )