Which recipe has the greatest ratio of honey to oats?

Recipe 3 has the greatest honey to oats ratio amongst the 4 recipes.

Step-by-step explanation:

Complete Question

Mr. Anderson has 4 recipes for granola. Recipe 1

A 2-column table with 3 rows is titled Recipe 1. Column 1 is labeled Honey (tablespoons) with entries 5, 10, 15. Column 2 is labeled Oats (cups) with entries 2, 4, 6.

Recipe 2

A 2-column table with 3 rows is titled Recipe 2. Column 1 is labeled Honey (tablespoons) with entries 6, 10, 14. Column 2 is labeled Oats (cups) with entries 3, 5, 7.

Recipe 3

A 2-column table with 3 rows is titled Recipe 3. Column 1 is labeled Honey (tablespoons) with entries 3, 6, 9. Column 2 is labeled Oats (cups) with entries 1, 2, 3.

Recipe 4

A 2-column table with 3 rows is titled Recipe 1. Column 1 is labeled Honey (tablespoons) with entries 8, 10, 12. Column 2 is labeled Oats (cups) with entries 4, 5, 6.

Which recipe has the greatest ratio of honey to oats?

Solution

Computing the ratio of honey to oats for each of recipes

Recipe 1

Honey | 5 | 10 | 15

Oats | 2 | 4 | 6

Honey to Oats ratio = (5/2) = (10/4) = (15/6) = 2.5 to 1.

Recipe 2

Honey | 6 | 10 | 14

Oats | 3 | 5 | 7

Honey to Oats ratio = (6/3) = (10/5) = (14/7) = 2 to 1.

Recipe 3

Honey | 3 | 6 | 9

Oats | 1 | 2 | 3

Honey to Oats ratio = (3/1) = (6/2) = (9/3) = 3 to 1.

Recipe 4

Honey | 8 | 10 | 12

Oats | 4 | 5 | 6

Honey to Oats ratio = (8/4) = (10/5) = (12/6) = 2 to 1.

Recipe 3 evidently has the greatest honey to oats ratio amongst the 4 recipes.

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2

faster, im not sure why but i know it is faster