A card is drawn from a standard deck of 52 playing cards. If the card is a club, a fair coin is flipped 9 times and the number of heads flipped is noted. If it is not a club, the coin is only flipped 3 times, but this time the result of each flip is noted. The card drawn is not noted in either case. How many elements are in the sample space for this experiment?

The sample space of an experiment is the set of possible outcomes of the experiment.

The elements in the sample space for the experiment are 18

When the outcome of the card is a club, the count of head that appears when the coin is flipped 9 times can be from 0 to 9 i.e. 10, in total

When the outcome of the card is not a club, the result of each flip when the coin is flipped 3 times is 2^3 i.e 8

So, the sample size is:

Hence, the elements in the sample space for the experiment are 18

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There are 18 elements in the sample space for this experiment

Step-by-step explanation:

Total cards = 52

Total outcomes on tossing a coin = 2   [1 head , 1 tail]

If the card is a club, a fair coin is flipped 9 times and the number of heads flipped is noted (but card drawn is not noted)).

Possible outcomes for heads = 0,1,2,...,9

So sample space for this event = {0,1,2,3,4,5,6,7,8,9} (Total 10 elements ) (i)

If it is not a club, the coin is only flipped 3 times, but this time the result of each flip is noted(but card drawn is not noted).

Sample space with all possible outcomes ={TTT,TTH, THT, HTT, HTH,HHT,THH,HHH}   (Total 18 elements )  (ii)

From (i) and (ii), Total elements in the sample space for this experiment = 10+8 = 18

Hence, there are 18 elements in the sample space for this experiment

8

step-by-step explanation:

this is a subtraction problem.

10 - 2 = 8

answer: 1, 3 and 5 are correct

step-by-step explanation: