What is the equation of a line in slope intercept form that contains the points (-4,3) and (2,-6)

y = (-3/2)x - 3

Step-by-step explanation:

The slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept.

Given two points, we can calculate the slope by dividing the change in y (or the difference in the y-coordinates) by the change in x (or the difference in the x-coordinates). Our two points are (-4, 3) and (2, -6):

m = (3 - (-6)) / (-4 - 2) = 9 / (-6) = -3/2

So, we can update our equation:

y = (-3/2)x + b

The y-intercept is where the graph crosses the y-axis, or the y-value where x = 0. Let's plug in 3 for y and -4 for x:

3 = (-3/2) * (-4) + b

3 = 6 + b

b = -3

So, our y-intercept is -3.

Our slope-intercept form is thus:

y = (-3/2)x - 3

~ an aesthetics lover

c is the final answer! : )

its the fourth option