Thomas needs to think of values for x that will cause the equations shown to be true. Can you come up with one or
more values for x that will work in the equation?
X(3 + x) = 0?

A: x=4
B: x= -4
C: x=0
D: x=0, x=4

C will make the equation true.  

Step-by-step explanation:

Replace the Xs with the value shown in the multiple choices.

1. 4(3 + 4) = 0

We know that 4x3 = 12 and 4x4 = 16, so..

12+16 = 0 FALSE

2. -4(3 - 4) = 0

(A negative times a negative will have a positive as the product)

-12 + 16 = 0 FALSE

3. 0(3 + 0) = 0

(Zero times a number will always have a zero as the product)

0 + 0 = 0 TRUE

4. 0(3 + 0) = 0 , 4(3 + 4) = 0

0 + 0 = 0 TRUE, 12 + 16 = 0 FALSE.  

2,600 divided by 80 = 32.5

step-by-step explanation:

the answer is y < -3 or   y > 3

-3y > 7 + 2

-3 y > 9

y < -3