Mr. Han is trying to decide how many new copies of a book to order for his students each book weighs 6 ounces which ordered pair is a variable solution if X represents the number of books he ordered and Y represents the total weight of the book in ounces

Options : (–3, –18) (–0.5, –3) (0, 0) (0.5, 3)

(0, 0)

Step-by-step explanation:

Given the following :

X = Number of books he ordered

Y = total weight of the book in ounces

Weight of each book = 6 ounces.

From the options provided,

(–3, –18) (–0.5, –3) (0.5, 3) aren't feasible options because of the following reasons.

The number of books ordered must be a whole number as it is impossible to order fraction of a book, hence, the ordered pair, (-0.5, - 3) and (0.5, 3) aren't viable solutions.

Also, the option (–3, –18) portrays a negative value and the number of books a person orders cannot be negative. Hence, the viable solution should be a positive whole number.

The only solution which seems viable is (0, 0) with x being 0 and y also. 0

If x = Number of books he ordered = 0

Ultimately, the total weight of the book in ounces will be (weight per book * number of books ordered)

= (6 ounces × 0) = 0

Hence, (0,0)

is there a question here?

step-by-step explanation:

hello from mrbilldoesmath!

answer:   x (x+6)^2, choice b

discussion:

factor x out of the equation:

x^3 + 12x^2 + 36x = x (x^2 + 12x + 36).

note that 6+6 = 12 and 6*6 = 36 so the above factors into:

x (x+6)^2

which is choice b

you,

mrb