Identify the height of a triangle in which b=(x−2) m and A=(x2−4) m2. A) h = (2x + 4) m B) h = (2x + 2) m C) h = (x + 2) m D) h = (x + 4) m show work is optional

we know that

area of triangle=b*h/2

b=(x-2) m

Area=(x²-4) m²

h=?

(x²-4)=(x+2)*h/2

but remember that

(x²-4)=(x+2)*(x-2)

so

subsititute

(x+2)*(x-2)=(x+2)*h/2

(x-2)=h/2

h=2*(x-2)

the answer is

the height of a triangle is 2*(x-2)

Step-by-step explanation:

the answer is 5/3x+7/5y+7

y=mx+