Help.. ill give brainliest..

(-6)-(+2)= -8

(-9)-(-8)= -17

(-6)-(+6)= -12

(-8)-(-8)= -16

(+5)-(+1)= 4

(+6)-(-2)= 8

(-3)-(+5)= -8

(-8)-(+5)= -13

(-9)-(-4)= -13

(+1)-(+3)= -2

(-3)-(+8)= -11

(+9)-(-4)= 13

(+8)-(-7)= 15

(-6)-(+3)= -9

(-3)-(+4)= -7

(-4)-(+3)= -7

(-6)-(+1)= -7

(+8)-(-8)= 16

(+1)-(+4)= -3

(+7)-(+9)= -2

(+5)-(-5)= 10

(+6)-(-9)= 15

(+7)-(-5)= 12

(+2)-(+1)= 1

(-6)-(+3)= -9

(+2)-(+9)= -7

(+1)-(+1)= 0

(-2)-(+3)= -5

(+3)-(+4)= -1

(+8)-(-9)= 17

the length of o'p' is .

step-by-step explanation:

it is given that the quadrilateral m'n'o'p' is the image of quadrilateral mnop after dilation.

the center of dilation is origin and the scale factor is 1.5.

in dilation the image and preimge are similar figures. it means the sides of image and preimage are proportional.

the scale factor is defined as

the scale factor is 1.5.

multiply both sides by op.

note: if the value of op is given, then multiply the value of op with 1.5 to get the length of side o'p'.

therefore length of o'p' is .

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240