Items 2-4. Points P, Q, and Sare collinear.
(3x - 5)
0
(x + 1)
s
2. What is the value of x?
3. What is m ZPQR?
will
11. M
4. If a ray QT bisects ZRQS, what
will be the measure of one of the
resulting angles?
m
of
5. Points L, M, and N are collinear.
You are given LM = 5 and LN = 17.
What is a possible value of MN?
Flb
6. Ray BD bisects ZABC so that
mZDBC = x + 6 and
mZABD = 2x - 12. What is x?

See below

Step-by-step explanation:

2

∠PQR and ∠RQS are supplementary, which add up 180°

Sum:

3

4

From the picture and the value of x we got above:

QT bisects ∠RQS and we get two equal angles

Each will measure:

5

LM = 5, LN = 17, MN = ?

If L is between M and N, then

M is between L and N, then

5

Ray BD bisects ∠ABC, then formed angles are equal:

m∠DBC = m∠ABD

answer:

(-8,7)

explanation:

we know that  

f

(

−

3

)

=

7

therefore, if we wish to get the output as 7, in the function, we need to have our input to be -3.

looking at the function  

f

(

x

+

5

)

, what should the value of x be, such that the input in the function becomes 7?

we simply equate the terms,

x

+

5

=

−

3

x

=

−

8

thus, the point on the new function would be  

(

−

8

,

7

)

the reporter's right

step-by-step explanation:

1/4 = .25 / 25%