The linear density of a rope is the ratio of its mass per unit length. It is given by the equation λ=ml, where λ is the linear density, m is the mass, and l is the length. If the linear density of a rope is given with units of gcm and the distance is given in units of cm, what would be the units for mass?

g = grams

Step-by-step explanation:

λ=ml,

where λ is the linear density,

m is the mass, and l is the length.

If the units of linear density of a rope = gcm

the distance = cm

Substituting these units into the formula

λ=ml

gcm = Mass × cm

Divide both sides by cm

Mass = gcm/cm

Mass = g

The unit of Mass is g

step-by-step explanation:

from the graph attached below:

domain of graph is the value of x for which the given function profit function p(x) is defined.

(a) the domain represents the number of years for which the outlet will earn a profit.

range of profit function defines the lowest to highest value of profit earned.

(b) the range of this function is (0 , 160 ). for this function, the range represents the outlet's profit earned.

the median here is 25. your lowest value is 14 and highest value is 48. to find the third quartile, find the medium number in between 25 and 48 which would be 42 i believe.