The perimeter of a rectangle is found by multiplying the sum of the length, shown as I, and the width, shown as w, by 2. The length of a certain rectangle is 20. Which
inequality shows that the perimeter of this rectangle is less than 57 units?
A.2 (20+w) > 57
B.2 (20 + w) < 57
C.2 (20) (w) > 57
D.2 (20) (w) < 57

Four equations are shown below. equation 1: y=2*equation 2: y=2x-5equation 3: y=x2 + 6equation 4: tdentify one linear equation and one nonlinear equation from the list. why each equation you identified is linear or nonlinear. nd one nonlinear equation from the list. state a reasonlinear equation

Given: ae ≅ ce ; de ≅ be prove: abcd is a parallelogram. we have that ab || dc. by a similar argument used to prove that △aeb ≅ △ced, we can show that △ ≅ △ceb by. so, ∠cad ≅ ∠ by cpctc. therefore, ad || bc by the converse of the theorem. since both pair of opposite sides are parallel, quadrilateral abcd is a parallelogram.

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