Mathematics, 20.09.2020 20:01 kevinbazalar

Jeremy wants to determine the number of solutions for the equation below without actually solving the equation. Negative 3 (x + 1) + 3 x = negative 3 (x minus 1) + 3 Which method should Jeremy use? Determine whether the equation has the form a = a, and if it does, the equation has infinitely many solutions. Determine whether the equation has the form a = b, and if it does, the equation has no solution. Determine whether the equation has the form x = a, and if it does, the equation has one solution. Determine whether the equation has the form x = 0, and if it does, the equation has no solution.

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