The stem plot shows the number of sit-ups completed by a group of gym members in one minute. Row1 with a 1 to the left of the bar with a 9 to the right. Row 2 with a 2 to the left of the bar with a 5 to the right. Row 3 with a 3 to the left of the bar with 4, 6, 8, 8 to the right. Row 4 with a 4 to the left of the bar with 0, 3, 6, 7, 7 to the right. Row 5 with a 5 to the left of the bar with 0, 0, 1, 2 to the right. Key: 1|9 = 19 sit-ups Which of the following is a correct statement about the distribution? There is one outlier. The distribution is skewed left. The center is around 47. The distribution is bimodal.

Only statement second is correct about the distribution.

Step-by-step explanation:

The stem plot data given to us is;

1 | 9

2 | 5

3 | 4   6   8   8

4 | 0   3   6   7   7

5 | 0   0   1    2

As it is given in the question that 1 | 9 = 19 sit-ups, so the data value are;

19, 25, 34, 36, 38, 38, 40, 43, 46, 47, 47, 50, 50, 51, 52

(a) The first statement that there is one outlier in the distribution is false as there are two outliers in the data (19 and 25) as they are very far from the rest of the data.

(b) The statement that the distribution is skewed left is correct because the tail of the distribution is towards the left.

(c) The statement that the center is around 47 is false as the center or mean of the data is 43 because the middle most data value is 43.

(d) The statement that the distribution is bimodal is false as there are is three modes in the data (38, 47 and 50), so the given distribution is trimodal.

hi! i think the answer is 1/2 : )