Find equations of the tangent lines to the curve given below at the points specified. y =
9 ln(x)
x
At the point (1, 0).
y =
At the point (e,9/e).
y =

Given :

y =  9 ln(x) , At the point (1, 0).

To Find :

Equations of the tangent lines to the curve given below at the points specified.

Solution :

Slope of tangent to curve at ( 1, 0) is :

Putting x = 1 , we get :

.

So , equation of tangent is :

Therefore , this is the required solution .

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