Listed below are systolic blood pressure measurements (mm Hg) taken from the right and left arms of the same woman. Assume that the paired sample data is a simple random sample and that the differences have a distribution that is approximately normal. Use a 0.05 significance level to test for a difference between the measurements from the two arms. What can be concluded? Right arm Left Arm
145 173
142 163
116 182
133 148
134 149
In this example,μd is the mean value of the differences d for the population of all pairs of data, where each individual difference d is defined as the measurement from the right arm minus the measurement from the left arm. What are the null and alternative hypotheses for the hypothesis test?
A. H0:μd≠0
H1:μd=0
B. H0:μd≠0
H1:μd>0
C. H0:μd=0
H1:μd≠0
D. Upper H0:μd=0
H1:μd<0
Identify the test statistic.
t=
(Round to two decimal places as needed.)
Identify the P-value.
P-value=
(Round to three decimal places as needed.)
What is the conclusion based on the hypothesis test?
Since the P-value is less/greaterthan the significance level, rejectfail to reject the null hypothesis. There is/is not sufficient evidence to support the claim of a difference in measurements between the two arms.

1.

The null hypothesis

H0: Ud=0

The alternate hypothesis

H1:Ud≠0

2. Test statistic = -3.04

3. P value = 0.039

4. Reject h0

Step-by-step explanation:

X = right arm

Y = left arm

d = difference between both arms

X. Y. d(x-y). d²

145. 173. -28. 784

142. 163. -21. 441

116. 182. -66. 4356

133. 148. -15. 225

134. 149. -15. 225

Total

d = -145

d² = 6031

We have sample space n = 5

d' = -145/5

= -29

Sd = √1/n-1(Σd²-(Σd)²/n

Sd = √1/4(6031-(-145)²/5

= √1/4(6931-4205)

= √456.5

= 21.366

To get t

=d'/(sd/√n)

= -29/(21.366/√5)

= -3.035

In summary

This is a two tailed test

1.

The null hypothesis

H0: Ud=0

The alternate hypothesis

H1:Ud≠0

2. Test statistic = -3.04

3. P value = 0.039

4. We have pvalue to be 0.039 which is less than the level of significance 0.05

0.039<0.05, so we take decision to reject h0 which is the null hypothesis

We have enough evidence to support claim that there is a measurement difference between left and right arms

answer: city needs 2.4 inches of rainfall more to match the record of 40 inches.

step-by-step explanation:

since we have given that

total annual rainfall a city record = 40 inches

this year, total rainfall recorded = 37.6 inches

number of inches of rainfall   is needed to match the record of 40 inches is given by

hence, city needs 2.4 inches of rainfall more to match the record of 40 inches.