What is the height of the building to the nearest tenth of a foot? (This is timed so help me ASAP please)

Height of the building = 18.3 ft

Step-by-step explanation:

Let the height of the building = x ft

From the picture attached,

A boy is standing on the building at a point A, car is at a point B and a bird is flying at C.

Applying Pythagoras theorem in ΔABD to find the distance AD.

AB² = BD² + AD²

AD =

     =

     =

     = 15 units

Now from ΔACD,

tan(70)° =

1.22196 =

x = 15 × 1.22196

x = 18.33

  ≈ 18.3 ft

Therefore, height of the building is 18.3 ft.

the answer is:

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