Write an equation and solve: Your math homework has 6 more than three times the number of problems you have on your history worksheet. If you have 42 problems to do for math and history, how many math problems do you have to complete for homework? (show as much work as possible)

33 math problems

Step-by-step explanation:

Let's set a few variables:

Number of math problems = m

Number of history problems = h

We know that in total, we have 42 problems.

m + h = 42

We also know that our math homework has 6 problems more than 3 times the number of history problems.

m = 3*h + 6

So m is 3 times h, plus 6.

m + h = 42

We can subtract h from both sides of this equation.

m = 42 - h

Now we can put this value for m, 42-h, into our other equation.

m = 3*h + 6

42 - h = 3*h + 6

Subtracting 6 from both sideS:

36 - h = 3*h

Adding h to both sides:

36 = 3*h + h

36 = 4*h

Dividing both sides by 4:

9 = h

h = 9

We know that the number of math problems is the following:

m = 42 - h

Let's put the value for h, 9, into this equation:

m = 42 - 9

m = 33

33 math problems

it is true

step-by-step explanation:

all the combinations add up i used   calculator

85.560%

step-by-step explanation:

conditional probability is defined as:

p(a|b) = p(a∩b) / p(b)

in other words, the probability that a occurs, given that b has occurred = the probability that both a and b occur / the probability that b occurs.

in this example:

p(turns 64 | turns 44) = p(turns 64 & turns 44) / p(turns 44).

if someone turns 64, they must have already turned 44, so:

p(turns 64 | turns 44) = p(turns 64) / p(turns 44)

on page 42, we see that of the original 100,000, 94944 turn 44, and 81234 turn 64.   therefore:

p(turns 64 | turns 44) = 81234 / 94944

p(turns 64 | turns 44) = 0.85560