On A4 paper; construct two equilateral triangles ΔABC and ΔPQR of side 5 cm and 3 cm respectively.
 Divide each side of ΔABC in 5 equal parts and ΔPQR in 3 equal parts.
 Now join the corresponding points so that the lines formed are parallel to the
respective sides of the triangle.
 Count the number of smaller triangles of same size formed in ΔABC and ΔPQR
 Using the above observations verify the result showing the mathematical
calculation

560

step-by-step explanation:

giggidy

the first option i believe

step-by-step explanation:

1. when "a" is a root of a polynomial, (x -a) is a factor of it. for the three roots given, the factors of the desired polynomial are (x +2)(x -1/2)(x -3).

in order to make the leading coefficient be negative, we need to multiply this product by a negative number. any negative number will do, but we choose a small (magnitude) value that will eliminate the fraction: -2.

then

f(x) = -2(x +2)(x -1/2)(x -3) = -(x +2)(2x -1)(x -3)

= -(2x² +3x -2)(x -3)

= -(2x³ -3x² -11x +6)

f(x) = -2x³ +3x² +11x -6

2. a graph created by the desmos on-line graphing calculator is shown, and the zeros are highlighted.

3. as indicated in part 1, the multiplier of this equation can be anything and the zeros will remain the same. you want a negative leading coefficient, so the "anything" is restricted to any of the infinite number of numbers that will make that be the case.

the answer for the second equation is (4,0)