Suppose that a visitor to Disneyland has a 0.74 probability of riding the Jungle Cruise, 0.62 probability of riding the Monorail, 0.70 of riding the Matterhorn, 0.52 of going on both the Jungle Cruise and Monorail, 0.46 of going on the Jungle Cruise and Matterhorn, 0.44 of going on the Monorail and the Matterhorn, and 0.34 of going on all three rides. What is the probability that a person visiting Disneyland will go on at least one of these three rides

0.98

Step-by-step explanation:

Let J denotes Jungle Cruise , M denotes Monorail and H denotes Matterhorn.

As per given ,

P(J) = 0.74,  P(M) =  0.62, P(H) = 0.70

P(J∩M) = 0.52,  P(J∩H)= 0.46 , P(M∩H)=0.44

P(J∩M∩H)=0.34

Now , the required probability:

P(J∪M∪H) = P(J) + P(M)  + P(H) - P(J∩M) - P(J∩H) - P(M∩H)+ P(J∩M∩H)

= 0.74+0.62+0.70-0.52-0.46-0.44+0.34

= 0.98

Hence, the probability that a person visiting Disneyland will go on at least one of these three rides= 0.98 .

17.08

correct me if i am wrong.

or

step-by-step explanation:

we need to solve for 'x' the following equation:  

we have that:

⇒

⇒ ⇒

factorizing, we get that:

  ⇒

then, the solutions are: or

nothing extraneous has been found!