The mean and standard deviation of a normal distribution are 150 and 12 respectively. What percentage of values lie between:
a) 138 and 162
b) 126 and 174
c) 126 and 162
d) 162 and 174

a) (150 - 138) / 12 = 1 deviation or 34%

(162 - 150) / 12 = 1 deviation or 34%

34% + 34% = 68%

b) (150 - 126) / 12 = 2 deviations or 47.5%

(174 - 150) / 12 = 2 deviations or 47.5%

47.5% + 47.5% =95%

c) (150 - 126) / 12 = 2 deviations or 47.5%

(162 - 150) / 12 = 1 deviation or 34%

47.5% + 34% = 81.5%

d) (162 - 150) / 12 = 1 deviation or 34%

(174 - 150) / 12 = 2 deviations or 47.5%

This problem is a little different. We have to subtract 34% from 47.5%

47.5% - 34% = 13.5%

i think is 3 and 6. this took me 10 min to think.hope to and hope that my answer is brainliest.(follow me )

correct choice is b

step-by-step explanation:

when you calculate the average rate of change of a function, you are finding the slope of the secant line between the two points. for the function the average rate of change from point to point can be calculated as

to find the average rate of change from day 2 to day 10, note that at day 2, 8 houses were sold, so a(2,8) and at day 10, 2 houses were sold, so b(10,2). thus,