7900 dollars is placed in an account with an annual interest rate of 5.25%. To the nearest tenth of a year, how long will it take for the account value to reach 34300
dollars?

Let’s take the interest rate (5.25%) and multiply it by 63.6 years, we get 3.339. Multiply 3.339 with $7900 (initial amount) and you’ll get $26,378.1 worth of interest money, add $7900 (initial amount) and $26,378.1 (interest money after 63.6 years), you’ll get $34,278.1 which is $34,300 rounded off to the nearest 100.

Therefore the answer to your question might be 70 years as after 63.6 years the account will have more than $34,300, therefore 60 years might not be the answer since then the amount would be lower than $34,300, but at year 70, a tenth of a year, the value in the account will be more than $34,300, so it will have at least reached $34,300 unlike at year 60 when the account value would be lower than $34,300 so it wouldn’t have even reached $34,300.

Answer = 70 years

First, think of what you know. you know that the number t the end of the equation will need to be subtracted because it is the money he lost from buying the lawn mower. and your first two weeks have negative profit, so that tells you that c and d are wrong. now you can plug any of the weeks into a and b to see which one works. i'll start with plugging week 1 into a.this isn't right because it says your answer for week one should be -90.so now we need to try the same thing with b.this one got you the right answer, (sometimes if you only check with one of the weeks multiple will work so you need to check with more of the weeks, but it worked out fine here)this means that b is the correct answer.let me know if you need more clarification. i hope this : )

Ci think but i'm not entirely sure so..