Q. Find the value of 'p' if the quadratic polynomial p(x) has
zeroes whose difference is 4,
where
p(x) = x2 + 8x + P

A. p = 6
B. p = 8
C. p = 10
D. p = 12

i need the options

step-by-step explanation:

step-by-step explanation:

the shape,the size and the distance

d is the answer

step-by-step explanation:

the polynomial is a perfect square trinomial of the form a^2-2ab+b^2:

option a. true

step-by-step explanation:

9x^2-12x+4

comparing with the form a^2-2ab+b^2

1.) a^2=9x^2

solving for a: square root both sides of the equation:

sqrt(a^2)=sqrt(9x^2)

a=sqrt(9) sqrt(x^2)

a=3x

2.) b^2=4

solving for b: square root both sides of the equation:

sqrt(b^2)=sqrt(4)

b=2

to be a perfet square trinomial 2ab must be equal to 12x. let's check:

2ab = 2 (3x) (2)

2ab = 12x

correct