How many liters each of a 30% acid solution and a 50 % acid solution must be used to produce 70 liters of a 40 % acid solution? (Round to two decimal places if necessary.)

  30%: 35 liters

  50%: 35 liters

Step-by-step explanation:

The desired concentration is halfway between the concentrations of available solutions, so the mixture will be equal amounts of each.

  35 liters of 30% acid and 35 liters of 50% acid must be used

If you want to write an equation, it usually works well to let the variable represent the amount of the most concentrated constituent: 50% acid. Then the amount of acid in the final mix is ...

  0.50x +0.30(70 -x) = 0.40(70)

  0.20x +21 = 28 . . . . simplify

  0.20x = 7 . . . . . . . . . subtract 21; next, divide by 0.20

  x = 35 . . . . . . amount of 50% solution (liters)

  70-x = 35 . . . amount of 30% solution (liters)

the nearest power is 1.651.

means 7482 to the 1.651th power is almost equal to 2489287

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1