Geometry Basics Test A polygon is said to be regular if all of its sides are the same length. Find the perimeter of the regular octagon
whose vertices are as follows.
(-2,-4), (1,0), (1,5), (-2,9), (-7,9), (-10,5), (-10,0), (-7,-4)
(1 point)
| units
Basic
7
8
9

P=40

Step-by-step explanation:

find the distance between each vertices:

between the following points to find the length of each sides, octagon has 8 sides , since it is regular pentagon the distance between each vertices =5

the length of each side of octagon=5

to check :d=√(x2-x1)²+(y2-y1)²

(-2,-4) and (1,0) , d=√[(1-(-2)]²+(0+4)² =√3²+4², d=5

(1,0) and (1,5)  , d= 5

(1,5) and (-2,9) ,  d=5

(-2,9) and (-7,9) , d=5

(-7,9) and (-10,5) , d=5

(-10,5) and(-10,0) , d=5

(-10,0) and(-7,-4), d= 5

(-7,-4) and (-2,-4), d=5

perimeter of octagon = 8a ( a is the length of the side)

p=8(5)

P=40

the answer is 28

step-by-step explanation:

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1