Find the product (x+2t) exponent of 2

x² + 4xtx + 4t²

Step-by-step explanation:

Given

(x + 2t)² = (x + 2t)(x + 2t)

Each term in the second factor is multiplied by each term in the first factor, that is

x(x + 2t) + 2t(x + 2t) ← distribute both parenthesis

= x² + 2tx + 2tx + 4t² ← collect like terms

= x² + 4tx + 4t²

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)

hi there!

first we need to find out how much they are adding to each number to make the next number.

ex: 4 + 4 = 8, 8 + 8 = 16, and so on.

so continuing with 32,

32 + 32 = 64

64 + 64 = 128

128 + 128 = 256

256 + 256 = 512

4, 8, 16, 32, 64, 128, 256, 512

the 8th term of the sequence will be 512

hope this ! ~