A water tank holds 486 gallons but leaking at a rate 4 gallons per week. A second water tank holds 648 gallons but is leaking at a rate of 7 gallons per week. After how many weeks will the amount of water in the 2 tanks? The amount of water that holds the two tanks will be the same in _ weeks.

The first tank contains

486 gal - (4 gal/week) t

gal of water after t weeks.

Similarly, the second tank contains

648 gal - (7 gal/week) t

gal of water.

The tanks hold the same amount of water when these two amounts are equal:

486 gal - (4 gal/week) t = 648 gal - (7 gal/week) t

(7 gal/week) t - (4 gal/week) t = 648 gal - 486 gal

(3 gal/week) t = 162 gal

t = (162 gal) / (3 gal/week)

t = 54 weeks

a

step-by-step explanation:

when a number is between two straight lines it means the absolute value.

to find absolute value you need to know how many numbers is that number away from 0.

when finding absolute value the number will always come out positive

so absolute value of -3 is 3

absolute value of 3/2 is 3/2

absolute value of -2 is 2

absolute value of 3.5 is 3.5

absolute value of -1 is 1

now put these numbers in order:

a)   |-1|, |3/2|, |-2|, |-3|, |3.5|