It is 3/4 h before closing time at the grocery store. it takes about 1/8 h for jane to find 1 item on her shopping list. how many items can she find before the store closes?
(a) create a model for the situation.
(b) use your model to find the solution. explain what you did. (c) state the solution as a full sentence.
!

Part a) Create a model for the situation

Let

x------>The number of items that Jane can find in h

we know that

It takes about h for Jane to find item on her shopping list

so

by proportion

Calculate How many items can she find in h

therefore

the answer part a) is

The model for the situation is

Part b) Use your model to find the solution

Solve for x

therefore

the answer part b) is

Part c) State the solution as a full sentence.

the answer Part c) is

It takes about h for Jane to find items on her shopping list

Jane finds a total of  6 items in 3/4 hours.

Step-by-step explanation:

Let x denote the number of items that Jane finds  at a grocery store in the required time.

Now it is given that:

It takes about 1/8 h for Jane to find 1 item on her shopping list.

This means that the time required by Jane to find  'x' items is:  x/8 h

Also, It is 3/4 h before closing time at the grocery store.

This means that the total time to find x items by Jane is equal to 3/4

i.e.

Hence, Jane finds 6 items in her shopping list in 3/4 h.

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

~

starting with:    

5 + x - 12 = 2x - 7   

5 + x - 12 - x = 2x - 7 - x (subtract x from both sides)   

5 - 12 = x - 7 (combine and cancel x's from both sides)   

5 - 12 + 7 = x - 7 + 7 (add 7 to both sides)   

0 = x (add numbers together on both sides)       

so in order for the equation to be true, x must be 0.   

trying x = -0.5   

5 + x - 12 = 2x - 7 (original equation)   

5 + -0.5 - 12 = 2(-0.5) - 7 (plug in value of x)   

5 + -0.5 - 12 = -1 - 7 (did multiplication)   

-7.5 = -8 (did addition on both sides)       

since -7.5 is obviously not equal to -8, the value of -0.5 for x is wrong.   

trying x = 0   

5 + x - 12 = 2x - 7 (original equation)   

5 + 0 - 12 = 2(0) - 7 (plug in value of x)   

5 + 0 - 12 = 0 - 7 (did multiplication)   

-7 = -7 (did addition on both sides)       

since -7 equals -7, that demonstrates that the value of 0 for x is correct.   

trying x = 1   

5 + x - 12 = 2x - 7 (original equation)   

5 + 1 - 12 = 2(1) - 7 (plug in value of x)   

5 + 1 - 12 = 2 - 7 (did multiplication)   

-6 = -5 (did addition on both sides)       

since -6 is obviously not equal to -5, the value of 1 for x is wrong.