F(x) = 3(x-4)2-2
Pls help me solve

x = 13/3

Step-by-step explanation:

Solve for x:

3×2 (x - 4) - 2 = 0

Hint: | Multiply 3 and 2 together.

3×2 = 6:

6 (x - 4) - 2 = 0

Hint: | Distribute 6 over x - 4.

6 (x - 4) = 6 x - 24:

6 x - 24 - 2 = 0

Hint: | Group like terms in 6 x - 24 - 2.

Grouping like terms, 6 x - 24 - 2 = 6 x + (-24 - 2):

6 x + (-24 - 2) = 0

Hint: | Evaluate -24 - 2.

-24 - 2 = -26:

6 x + -26 = 0

Hint: | Isolate terms with x to the left hand side.

Add 26 to both sides:

6 x + (26 - 26) = 26

Hint: | Look for the difference of two identical terms.

26 - 26 = 0:

6 x = 26

Hint: | Divide both sides by a constant to simplify the equation.

Divide both sides of 6 x = 26 by 6:

(6 x)/6 = 26/6

Hint: | Any nonzero number divided by itself is one.

6/6 = 1:

x = 26/6

Hint: | Reduce 26/6 to lowest terms. Start by finding the GCD of 26 and 6.

The gcd of 26 and 6 is 2, so 26/6 = (2×13)/(2×3) = 2/2×13/3 = 13/3:

x = 13/3

d. vertex

step-by-step explanation:

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)