A yard has a perimeter of 400 feet. If eight times the length of the yard equals seventeen times the width, what are its dimensions?

Length of the rectangular yard = 136 feet

Width of the rectangular yard = 64 feet

Step-by-step explanation:

Let

Width = 17 × width

Length = 8 × length

8l = 17w

l = 17w/8

Perimeter of a rectangular yard = 2(length + width)

400 = 2(17w/8 + w)

400 = 34w/8 + 2w

400 = 17/4w + 2w

400 = 17w+8w/4

400 = 25w/4

Cross product

1600 = 25w

Divide both sides by 25

w = 1600/25

= 64 feet

Recall,

l = 17w/8

= 17*64 / 8

= 1088/8

= 136 feet

Length of the rectangular yard = 136 feet

Width of the rectangular yard = 64 feet

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine

g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)