Four pounds of apples cost $5. eight pounds of apples cost $10. if the total cost of apples, y, varies directly with the number of pounds of apples purchased, x, what is the cost of 6 pounds of apples? round your answer to the nearest hundredth.

The cost of the 6 pounds of apples is $7.5 .

Step-by-step explanation:

As y = Total cost of the apple.

    x =  The number of pounds of apples purchased .

As given

If the total cost of apples, y, varies directly with the number of pounds of apples purchased, x.

i.e

y = kx

Where k is the constant of proportionality .

As given

Four pounds of apples cost $5.

x = 4 , y = 5

Put in y = kx

5 = 4k

k = 1.25

Eight pounds of apples cost $10.

x = 8 , y = 10

Put in y = kx

10 = 8k

k = 1.25

Now find out the cost of 6 pounds of apples.

x = 6 and k = 1.25

Put in the y = kx

y = 6 × 1.25

y = $7.5

Therefore the cost of the 6 pounds of apples is $7.5 .

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)  

-4, -2, 1, 4

step-by-step explanation:

domain = x values

range = y values