The greater of two consecutive EVEN numbers is 40 less than twice the smaller number. Find the larger number

Step-by-step explanation:

z -  some integer

2z - first given even integer (the smaller one)

2z+2 - even integer consecutive to 2z  (the larger one)

2(2z)    - twice the smaller number

2(2z) - 40    - the number 40 less than twice the smaller number

2(2z) - 40 = 2z + 2

4z - 40 = 2z + 2

2z = 42

2z+2 = 42+2 = 44

check:

2(2z)-40 = 2(42)-40 = 84-40 = 44

boxplot e is the answer

-7/8

step-by-step explanation:

instead of subtracting you add the -6/8 and -1/8