The interval for which the quotient is continuous is the intersection of the above intervals. therefore, the quotient 12 x 12 x is continuous on the interval

The common continuous interval will be (0,∞).

Step-by-step explanation:

Given that,

The numerator = 12+√x

The denominator = √12+x

We know that,

For the numerator,

Any function under square root should be greater than and equal to the zero.

So, the continuous interval is (0, ∞)

For the denominator,

The interval for the continuous and non zero function is,

(-12, ∞)

We need to calculate the continuous interval

Using given quotient

The continuous interval of numerator and  denominator are (0, ∞) and (-12, ∞).

Hence, The common continuous interval will be (0,∞).

yes yes yes yes yes yes yes yes yes

answer: option a.

step-by-step explanation:

you know that the quadrilateral opqr ( a four sided figure) is inscribed in circle. this means that all its vertices are on the circle.

then, by definition, the opposite angles of the quadrilateral are supplementary, this means that the sum of their measures is 180 degrees.

you can observe in the figure that the angles ∠opq   and the angle ∠orq   are opposite, therefore:

then, can be used to d to calculate the measure of ∠opq