M angle ABF=(7x+20)^ ,m angle FBC=[2x-5)^ and m angle ABC=159^ , find the value of x.

19 1/3°

Step-by-step explanation:

Given the expressions ABF=(7x+20)° m angle FBC=[2x-5)° and m angle ABC=159°

The addition properties is there fore true for the three angles;

<ABC = <ABF+<FBC

159 = 7x+20+2x-5

159 = 9x-15

Add 15 to both sides

159+15 = 9x-15+15

174 = 9x

9x = 174

Divide both sides by 9

9x/9 = 174/9

x = 19 1/3°

The value of x is 19 1/3°

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step-by-step explanation:

step-by-step explanation:

i found the life tables for the year 2012. 

life table of males at age 30. probability of dying between ages x and x+1

total population:  

29–30 . . . . . . . . . . . . 0.001030

30–31 . . . . . . . . . . . . 0.001061

males:  

29–30 . . . . . . . . . . . . 0.001420

30–31 . . . . . . . . . . . . 0.001448

white population

29–30 . . . . . . . . . . . . 0.001005

30–31 . . . . . . . . . . . . 0.001037

white males

29–30 . . . . . . . . . . . . 0.001372

30–31 . . . . . . . . . . . . 0.001399

non hispanic white population

29–30 . . . . . . . . . . . . 0.001083

30–31 . . . . . . . . . . . . 0.001116

non hispanic white males

29–30 . . . . . . . . . . . . 0.001477

30–31 . . . . . . . . . . . . 0.001503

jacob, non hispanic white male. 30 years old.

probability that jacob lives to be 30 years old. 

since the given probabilities are probabilities of dying, i think we simply subtract it from 1 to get the probability of living. we will use the probability of non hispanic white male.

                                          probability of living to be 30 y.o.

29 - 30 : 1 - 0.001477 = 0.998523

30 - 31 : 1 - 0.001503 = 0.998497