Canteen A, canteen B and Canteen C repeat their lunch means every 12 days, 8days and 10 days respectively. All three canteens serve noodles soup today. How many days later will all three canteen serving noodles soup again?

120 days

Step-by-step explanation:

Canteen A = 12 days

Canteen B = 8 days

Canteen C = 10 days

How many days later will all three canteen serving noodles soup again?

To find the number of days all 3 canteens will serve food again, find the lowest common multiples of all 3 canteens

Canteen A = 12 days

34, 36, 48, 60, 72, 84, 96, 108, 120, 132, 144

Canteen B = 8 days

16, 24, 32, 40, 48, 56, 64, 72, 80, 88, 96, 104, 112, 120

Canteen C = 10 days

20, 30, 40, 50, 60, 70, 80, 90, 100, 110, 120, 130

The lowest common multiple of 12 days, 8 days and 10 days is 120 days

The next day all 3 canteens will serve soup together again is the next 120 days

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions