The first aircraft has 68 more seats than the second aircraft. The third aircraft has 44 fewer seats than the second aircraft. If their total number of seats is 402, find the number of seats for each aircraft

Aircraft 1 has 194 seats, Aircraft 2 has 126 seats, and Aircraft 3 has 82 seats.

Step-by-step explanation:

In order to solve the present problem, an equation must be formulated. Thus, if the first aircraft has 68 seats more than the second one, and the third one has 44 fewer seats than the second aircraft, we can establish the following values:

Aircraft 1: X + 68

Aircraft 2: X

Aircraft 3: X - 44

Therefore, the equation could be stated as follows:

X + 68 + X + X - 44 = 402

3X = 402 + 44 - 68

3X = 378

X = 378/3

X = 126

So, Aircraft 1 will have 194 seats (126 + 68), Aircraft 2 will have 126 seats, and Aircraft 3 will have 82 seats (126 - 44).