Find a point on the line y = 4 that is equidistant from the two points (0,1) and (5,6)

The point on the line that is equidistant from points (0,1) and (5,6) is (2, 4).

Step-by-step explanation:

Let be , and . As we know that given function is a horizontal line, the condition of equidistance between that a point within that line and both points must be:

Where:

- Distance of point A with respect to P.

- Distance of point B with respect to P.

We expand this equivalence by Pythagorean Theorem:

And we get this expression:

If we know that , , , and , the expression is reduced to this:

The remaining component of the point within the line is:

The point on the line that is equidistant from points (0,1) and (5,6) is (2, 4).

536

step-by-step explanation:

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it