Hi ! can someone help me and tell me if my answers right or wong Thank you

1.  a) discriminant

              4.  b) No. when < 0 it has no Real solutions

Step-by-step explanation:

All of the other answers are correct.

In the quadratic expression, the solutions are defined by the discriminant (b² - 4ac) as follows:

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

what are ur choices?