Solve the one-variable equation using the distributive property and properties of equality. –6(2 + a) = –48

a =6

Step-by-step explanation:

–6(2 + a) = –48

Distribute

-12 -6a = -48

Add 12 to each side using the addition property of equality

-12+12 -6a = -48+12

-6a = -36

Divide each side by -6 using the division property of equality

-6a/-6 = -36/-6

a = 6

Steps to solve:

-6(2 + a) = -48

~Distribute left side

-12 - 6a = -48

~Add 12 to both sides

-6a = -36

~Divide -6 to both sides

a = 6

Best of Luck!

not enough information

step-by-step explanation:

we cannot know this, because the other students could have handed out 10 flyers, or they could have handed out 100. one way, the mean would go up, and another way, the mean would go down.

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.