How many liters each of a 25% acid solution and a 65% acid solution must be used to produce 80 liters of a 45% acid solution? (Round to two decimal places if necessary.)

40 liters of 25% solution and 40 liters of 65% solution

Step-by-step explanation:

Let x = volume of 25% solution.

Let y = volume of 65% solution.

Equation of total volume:

x + y = 80

Equation of amount of acid:

0.25x + 0.65y = 0.45(80)

0.25x + 0.65y = 36

Solve x + y = 80 for x.

x = 80 - y

Substitute into the second equation.

0.25(80 - y) + 0.65y = 36

20 - 0.25y + 0.65y = 36

0.4y = 16

y = 40

x + y = 80

x + 40 = 80

x = 40

40 liters of 25% solution and 40 liters of 65% solution

whatever you can spend with $11.53 or under.

step-by-step explanation:

20 - 8.47 = 11.53. take away the money he used for lunch from the starting amount of 20.

the answer is somewhere there guys it really . there im just not gonna answer

step-by-step explanation:

but i'm guessing ur first option tho