Please Help! (I have had trouble with this question for a while.)

The difference of the roots of the quadratic equation is . If , then find in terms of .

Below

Step-by-step explanation:

The equation is x2 + bx + c

The coefficients are

● a = 1

● b

● c is the constant

The difference of the roots is | b - 2c |

Let s and p be the roots of the polynomial

● s - p = | b - 2c | (1)

● s + p = -b/a => s + p = -b (2)

(1) + (2)

● s - p + s + p = |b-2c| - b

● 2s = | b - 2c | - b

● 2s = b - 2c - b or 2s = 2c - b - b

● 2s = - 2c or 2s = 2c - 2b

● s = - c or s = c - b

We want to express b in term of c. So we will be intetsted in the 2nd equation

● s = c - b

● s - c = - b

● b = c - s

took the test it's 94

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3