from the number of cards number from 7 to 27 a card is drawn at random. find probability of getting card a prime or even number.

16/21

Step-by-step explanation:

1) first determine the sample you are studying

27,26,25,24,23,22,21,20,19,18,17,16,15, 14,13,12,11,10,9,8,7

We have 21 different cards

Let S be the total number of cards

● S = 21

Let's determine wich are containing a prime number

● 7 is a prime number

● 8,9,10 are not

● 11 is a prime number

● 12 is not

● 13 is a prime number

● 14,15,16 are not

● 17 is

● 18 is not

● 19 is

● 21,22 are not

● 23 is

● 24,25,26,27 are not

So the cards with a prime number are

7, 11, 13, 17, 19 and 23

Wich means 6 cards

Now let's determine the cards with an even number

● 8,10,12,14,16,18,20,22,24 and 26

Wich means 10 cards

Now let's see the total number of cards that represent the event T ( having a prime or an even card)

We have 6 prime cards and 10 even ones

● T = 6 + 10 = 16

2) calculating the probability

● P(T) = T/S = 16/21

So the probability of picking a prime or an even card is 16/21

i found two solutions,   n = 2 • ± √3 = ± 3.4641

step-by-step explanation:

the data of the detroit pistons in numerical order from least to greatest is 0.30, 0.37, 0.55, 0.62, 0.69, 0.72, 0.73, 0.75, 0.77, 0.78, 0.80, 0.81, 0.81, 0.83, 0.84, 0.89

the data of the miami heat in numerical order from least to greatest is 0.50, 0.50, 0.56, 0.57, 0.67, 0.72, 0.72, 0.72, 0.75, 0.75, 0.76, 0.81, 0.82, 0.90, 1.00, 1.00

the detroit pistons median : 1.52

the miami heat median: 1.47

the iqr of this data is 0.05