6y – 5 = –3(2y + 1) please solve

Step-by-step explanation:

So we have the equation:

First, distribute the right side:

Add 6y to both sides. The right cancels:

Add 5 to both sides. The left cancels:

Divide both sides by 12:

Reduce:

And we're done!

Steps to solve:

6y – 5 = –3(2y + 1)

~Distribute left side

6y - 5 = -6y - 3

~Add 5 to both sides

6y = -6y + 2

~Add 6y to both sides

12y = 2

~Divide 12 to both sides

y = 1/6

Best of Luck!

m∠5 + m∠3 = m∠1   is true.

m∠5 + m∠6 = 180 is true

m∠2 +m∠3 = m∠6   is true

m∠2 +m∠3 +m∠5 = 180   is true