Find a quadratic equation whose roots are
3-

x² - 6x + 6 = 0

Step-by-step explanation:

Given the roots are x = 3 - and x = 3 + , then the corresponding factors are

(x - (3 - ) ) and (x - (3 + ) ), that is

(x - 3 + ) and (x - 3 - )

The equation is then the product of the factors

(x - 3 + )(x - 3 - ) = 0

(x - 3)² - ( )² = 0

x² - 6x + 9 - 3 = 0

x² - 6x + 6 = 0

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

black lol

step-by-step explanation:

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i can tell you jamal now has 3 cookies xd

tommy has 2.

this made me lol.