Mathematics, 04.09.2020 20:01 goodluck99

EMERGENCY The figure below can be used to prove the Pythagorean Theorem. Use the drop down menus to complete the proof. Click the arrows to choose an answer from each menu.

EMERGENCY The figure below can be used to prove the Pythagorean Theorem. Use the drop down menus to

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Answer from: hsbhxsb

Follow along and see the highlighted bold text for the drop-down answers.

Our first option is asking for the expression which is the sum of the area of:

a. the shaded triangles

and b. the white square

The area of the shaded triangles can be found by using the formula for the area of a triangle.

A = (base * height) / 2

On these triangles, the base is b and the height is a.

$A=\frac{b*a}{2}$

Since there are 4 triangles, we'll multiply this expression by 4.

$A=4*\frac{ba}{2}=\frac{4ba}{2}=2ba$

The area of the white square can be found using the formula for the area of a square.

A = side * side = side^2

The side of our square is c.

A=c^2

The sum of these areas is, thus:

A=2ba+c^2 (our first expression)

The area of the larger square, the entire figure, can be found using the formula for the area of a square that we used above. The side of this square is (a + b):

A=(a+b)^2=a^2 +2ab + b^2 (our 2nd expression)

We also choose to expand the parenthesis using the appropriate rule to get the above expression.

Now, following the proof, we set both of these expressions equal to each other and subtract something. Let's put these 2 expressions (the sum of the triangle and the white square, and the larger square) equal to each other:

2ba+c^2=a^2+2ab+b^2

Since 2ba = 2ab, we can subtract this from both sides. (we subtract 2ab)

c^2=a^2+b^2

Flipping this equation, we get the Pythagorean Theorem:

a^2+b^2=c^2

Answer from: Quest

Hello! mark me brainliest
answer:
congruent segments
step-by-step explanation:
congruent segments. take a line, cut it in half, superipose one half over the other half; you'll have congruence.

Answer from: Quest

Answer: f(x) = -2x^3 +3x^2 +11x -6see attachedan infinite number. since the magnitude of the leading coefficient is not specified, it may be any negative number. (we have chosen the smallest magnitude integer that makes all coefficients be integers.)step-by-step explanation:

1. when "a" is a root of a polynomial, (x -a) is a factor of it. for the three roots given, the factors of the desired polynomial are (x +2)(x -1/2)(x -3).

in order to make the leading coefficient be negative, we need to multiply this product by a negative number. any negative number will do, but we choose a small (magnitude) value that will eliminate the fraction: -2.

then

f(x) = -2(x +2)(x -1/2)(x -3) = -(x +2)(2x -1)(x -3)

= -(2x² +3x -2)(x -3)

= -(2x³ -3x² -11x +6)

f(x) = -2x³ +3x² +11x -6

2. a graph created by the desmos on-line graphing calculator is shown, and the zeros are highlighted.

3. as indicated in part 1, the multiplier of this equation can be anything and the zeros will remain the same. you want a negative leading coefficient, so the "anything" is restricted to any of the infinite number of numbers that will make that be the case.

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EMERGENCY The figure below can be used to prove the Pythagorean Theorem. Use the drop down menus to...