Find the perimeter of quadrilateral ABCD with vertices A(-2,-2), B(-1,3),
C(5, 3), and D(4, -2).

10010010001010010101001001010010100101010010101010010010101010110010001011010010010001

step-by-step explanation:

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation:

it is 10.6 according to my calculations

let's fu(!

step-by-step explanation: