Factor by using the difference of squares method: 36x^4 - 4x^2 A. (6x^2 – 2x)(6x^2 - 2x) = 4x^2(3x - 1)(3x - 1)
B. (6x^2 + 2x)(6x^2 + 2x) = 2x^2(3x + 1)(2x + 1)
C. (-6x^2 – 2x)(-6x^2 - 2x) = 4x^2(-3x - 1)(-3x - 1)
D. (6x^2 – 2x)(6x^2 + 2x) = 4x^2(3x - 1)(3x + 1)
E. (-6x^2 + 2x)(6x^2 - 2x) = 2x^2(-3x + 1)(3x - 1)
C. This polynomial cannot be factored by using the difference of squares method.

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Given: lines a and b are parallel and line c is a transversal. prove: 2 is supplementary to 8 what is the missing reason in the proof? statement reason 1. a || b, is a transv 1. given 2. ∠6 ≅ ∠2 2. ? 3. m∠6 = m∠2 3. def. of congruent 4. ∠6 is supp. to ∠8 4. def. of linear pair 5. ∠2 is supp. to ∠8 5. congruent supplements theorem corresponding angles theorem alternate interior angles theorem vertical angles theorem alternate exterior angles theorem